Arithmetic Progression (AP), also called Arithmetic Sequence, is a type of number pattern where the difference between two consecutive terms is always the same.
Example: The natural numbers 1, 2, 3, 4, 5, … form an AP because each number increases by 1.
Example: The even numbers 2, 4, 6, 8, … also form an AP because each number increases by 2.
We see such patterns everywhere in daily life - roll numbers in a class, days of the week, or months in a year. That’s why Arithmetic Progression is one of the most useful concepts in mathematics.
Table of Contents
In mathematics, a progression is a sequence of numbers that follows a rule. There are mainly three types of progressions:
Arithmetic Progression (AP)
Geometric Progression (GP)
Harmonic Progression (HP)
Out of these, AP is the simplest and most commonly used.
Definition 1: An AP is a sequence of numbers where the difference between two consecutive terms is always constant.
Definition 2: In an AP, every term after the first is obtained by adding the same fixed number (called the common difference) to the previous term.
Example: 3, 6, 9, 12, … has a common difference of 3.
When we talk about an AP, we usually use:
a = first term
d = common difference
an = nth term
Sn = sum of first n terms
If the first term is a, then the sequence looks like:
a, a + d, a + 2d, a + 3d, …, a + (n – 1)d
If an AP is a1, a2, a3, …, then:
d = a2 – a1 = a3 – a2 = … = an – an-1
The value of d can be positive, negative, or zero.
Position of Term |
Representation |
Formula |
1 |
a1 |
a = a + (1-1)d |
2 |
a2 |
a + d = a + (2-1)d |
3 |
a3 |
a + 2d = a + (3-1)d |
n |
an |
a + (n-1)d |
Formula:
an = a + (n – 1) × d
Example: Find the 15th term of AP: 1, 2, 3, …
a = 1, d = 1, n = 15
a15 = 1 + (15 – 1) × 1 = 15
Finite AP - An AP that has a limited number of terms.
Example: 5, 10, 15, 20, 25
Infinite AP - An AP that continues endlessly without a last term.
Example: 2, 4, 6, 8, 10, …
The formula is:
Sn = n/2 [2a + (n – 1) × d]
If the last term l is known, then:
Sn = n/2 (a + l)
Example: Find the sum of first 15 natural numbers.
a = 1, d = 1, n = 15
Sn = 15/2 [2(1) + (15 – 1)(1)]
= 15/2 [2 + 14] = 15 × 8 = 120
Formula |
Expression |
General Form |
a, a + d, a + 2d, … |
nth Term |
an = a + (n – 1)d |
Sum of n Terms |
Sn = n/2 [2a + (n – 1)d] |
Sum with Last Term |
Sn = n/2 (a + l) |
Example 1: If a = 10, d = 5, and an = 95, find n.
Solution: 95 = 10 + (n – 1)5 → n = 18
Example 2: Find the 20th term of AP: 3, 5, 7, 9…
Solution: a = 3, d = 2, n = 20 → a20 = 41
Example 3: Find the sum of first 30 multiples of 4.
Solution: a = 4, d = 4, n = 30
S30 = 30/2 [2(4) + (30 – 1)(4)] = 1860
Find the 10th term of 3, 1, 17, 24, …
If a = 2, d = 3, n = 90, find an and Sn.
The 7th term is 12 and the 10th term is 25. Find the 12th term.
Answer. a, a + d, a + 2d, …, a + (n – 1)d
Answer. The sequence 5, 10, 15, 20, … is an AP with common difference 5.
Answer. Use the formula Sn = n/2 [2a + (n – 1)d].
Answer. Arithmetic Progression (AP), Geometric Progression (GP), Harmonic Progression (HP).
Answer. AP is used in predicting patterns, like calculating salary hikes, cab arrival time at equal intervals, or arranging seats in rows.
Explore more engaging concepts like Arithmetic Progression at Orchids International School- share and help others master the world of sequences!
CBSE Schools In Popular Cities